KCET · Chemistry · Aldehydes and Ketones

The product ' \(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product \(C\). The compound \(C\) is heated strongly to form product \(D\). The product \(D\) is
- A 4-methylpent-3-en-2-one
- B but-2 enal
- C 3-methylpent-3-en-2-one
- D 2-methylbut-2-enal
Answer & Solution
Correct Answer
(A) 4-methylpent-3-en-2-one
Step-by-step Solution
Detailed explanation
The given reaction take place in following way

Phenol gives white ppt. with bromine water.
Acetone when treated with \(\mathrm{Ba}(\mathrm{OH})_{2}\) undergoes aldol condensation as follows


\(\therefore\) The product \(D\) is 4-methylpent-3-en-2-one.

Phenol gives white ppt. with bromine water.
Acetone when treated with \(\mathrm{Ba}(\mathrm{OH})_{2}\) undergoes aldol condensation as follows


\(\therefore\) The product \(D\) is 4-methylpent-3-en-2-one.
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