KCET · Chemistry · d and f Block Elements
A member of the Lanthanoid series which is well known to exhibit +4 oxidation state is
- A Samarium
- B Europium
- C Erbium
- D Cerium
Answer & Solution
Correct Answer
(D) Cerium
Step-by-step Solution
Detailed explanation
\(\mathrm{Ce}:[\mathrm{Xe}] 4 \mathrm{f}^1 5 \mathrm{~d}^1 6 \mathrm{~s}^2\)
\(\mathrm{Ce}^{+4}:[\mathrm{Xe}] 4 \mathrm{f}^{\circ} 5 \mathrm{~d}^{\circ} 6 \mathrm{~s}^{\circ}\)
Since \(\mathrm{Ce}^{+4}\) has stable noble gas configuration, it is well known to show +4 oxidation sate.
\(\mathrm{Ce}^{+4}:[\mathrm{Xe}] 4 \mathrm{f}^{\circ} 5 \mathrm{~d}^{\circ} 6 \mathrm{~s}^{\circ}\)
Since \(\mathrm{Ce}^{+4}\) has stable noble gas configuration, it is well known to show +4 oxidation sate.
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