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KCET · Physics · Wave Optics

In a Fraunhofer diffraction experiment at a single slit using a light of wavelength \(400 \mathrm{~nm}\), the first minimum is formed at an angle of \(30^{\circ}\). The direction \(\theta\) of the first secondary maximum is given by

  1. A \(\sin ^{-1}\left(\frac{2}{3}\right)\)
  2. B \(\sin ^{-1}\left(\frac{3}{4}\right)\)
  3. C \(\sin ^{-1}\left(\frac{1}{4}\right)\)
  4. D \(\tan ^{-1}\left(\frac{2}{3}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sin ^{-1}\left(\frac{3}{4}\right)\)

Step-by-step Solution

Detailed explanation

For first diffraction minimum
\[
\Rightarrow \quad \begin{aligned}
a \sin \theta &=\lambda \\
a &=\frac{\lambda}{\sin \theta}
\end{aligned}
\]
For first secondary maximum
\[
a \sin \theta^{\prime}=\frac{3 \lambda}{2}
\]
or \(\sin \theta^{\prime}=\frac{3 \lambda}{2} \times \frac{1}{a}=\frac{3 \lambda}{2} \times \frac{\sin \theta}{\lambda}=\frac{3}{2} \times \sin 30^{\circ}=\frac{3}{4}\)
or
\[
\theta^{\prime}=\sin ^{-1}\left(\frac{3}{4}\right)
\]