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KCET · Physics · Semiconductors

If \( A=1 \) and \( B=0 \), then in terms of Boolean algebra, \( \bar{A}+B= \)

  1. A \( B \)
  2. B \( \bar{B} \)
  3. C \( A \)
  4. D \( \bar{A} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( B \)

Step-by-step Solution

Detailed explanation

\( A=1, B=0 \)
\( \bar{A}+B=1+0=0+0=0 \)
\( \bar{A}+B=B \)