The dimensions of the ratio of magnetic flux \( (\phi) \) and permeability \( (\mu) \) are

Magnetic flux, \(\phi=B A \rightarrow(1)\)
where \(B\) is magnetic field; \(A\) is area.
Also, \(B=\mu H \rightarrow(2)\)
where \(\mu\) is permeability; \(H\) is magnetic field intensity
Substituting Eq. (2) in Eq. (1), we get
\(\phi=(\mu H) A\)
or \(\frac{\phi}{\mu}=H A\)
Now, Area A has dimensions \(L^{2}\)
And magnetic field intensity \(H=\frac{\text { Number of turns } \times \text { Current }}{\text { Metre }}\)
\(\Rightarrow H\) has dimensions \(L^{-1} A .\)
Therefore, \(\frac{\phi}{\mu}=L^{-1} A \times L^{2}=L A\)
Hence, the dimensions of ratio of magnetic flux and permeability \(\mu\) are \(\left[M^{0} L^{1} T^{0} A^{1}\right]\)