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KCET · Physics · Waves and Sound

How many times more intense is a \(60 \mathrm{~dB}\) sound than a \(30 \mathrm{~dB}\) sound?

  1. A 1000
  2. B 2
  3. C 100
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(A) 1000

Step-by-step Solution

Detailed explanation

\(\mathrm{L}=10 \log _{10} \frac{\mathrm{I}}{\mathrm{I}_{0}}\)
\(60=10 \log _{10} \frac{\mathrm{I}_{1}}{\mathrm{I}_{0}}\)
\(\Rightarrow \frac{\mathrm{I}_{1}}{\mathrm{I}_{0}}=10^{6}\)
Similarly,
\(\begin{aligned}&30=10 \log _{10} \frac{\mathrm{I}_{2}}{\mathrm{I}_{0}} \\&\frac{\mathrm{I}_{2}}{\mathrm{I}_{0}}=10^{3}\end{aligned}\)
Dividing Eq. (i) by Eq. (ii), we get
\(\frac{\mathrm{I}_{1}}{\mathrm{I}_{2}}=1000\)