KCET · Physics · Ray Optics
A plano-convex lens is made of refractive index of 1.6. The radius of curvature of the curved surface is \(60 \mathrm{~cm}\). The focal length of the lens is
- A \(400 \mathrm{~cm}\)
- B \(200 \mathrm{~cm}\)
- C \(100 \mathrm{~cm}\)
- D \(50 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(100 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Here, \(\frac{1}{\mathrm{f}}=(\mu-1)\left[\frac{1}{\mathrm{R}_{1}}-\frac{1}{\mathrm{R}_{2}}\right]\)
\(\frac{1}{f}=(1.6-1)\left[\frac{1}{60}-\frac{1}{\infty}\right]=\frac{1}{100}\)
\(\Rightarrow \quad \mathrm{f}=100 \mathrm{~cm}\)
\(\frac{1}{f}=(1.6-1)\left[\frac{1}{60}-\frac{1}{\infty}\right]=\frac{1}{100}\)
\(\Rightarrow \quad \mathrm{f}=100 \mathrm{~cm}\)
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