KCET · Maths · Determinants
Let \( A \) be a square matrix of order \( 3 \times 3 \), then \( |5 A|= \)
- A \( 5|A| \)
- B \( 125|A| \)
- C \( 25|\mathrm{~A}| \)
- D \( 15|A| \)
Answer & Solution
Correct Answer
(B) \( 125|A| \)
Step-by-step Solution
Detailed explanation
We know that, for \( n \times n \) matrix \( |k A|=k^{n}|A| \).
So, for \( 3 \times 3 \) matrix is
\( |5 A|=5^{3}|A|=125|A| \)
So, for \( 3 \times 3 \) matrix is
\( |5 A|=5^{3}|A|=125|A| \)
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