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KCET · Maths · Inverse Trigonometric Functions

Let \(f:[2, \infty) \rightarrow R\) be the function defined \(f(x)=x^{2}-4 x+5\), then the ranges of \(f\) is

  1. A \((-\infty, \infty)\)
  2. B \([1, \infty)\)
  3. C \((1, \infty)\)
  4. D \([5, \infty)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \([1, \infty)\)

Step-by-step Solution

Detailed explanation

We have,
\(\begin{aligned}
&f(x)=x^{2}-4 x+5 \\
&f(x)=x^{2}-4 x+4+1 \\
&f(x)=(x-2)^{2}+1
\end{aligned}\)
\(\therefore\) Range of \(f(x)\) is \([1, \infty)\).