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KCET · Maths · Trigonometric Equations

If \(\sin 2 x=4 \cos x\), then \(x\) is equal to

  1. A \(\frac{\mathrm{n} \pi}{2} \pm \frac{\pi}{4}, \mathrm{n} \in \mathrm{Z}\)
  2. B no value
  3. C \(n \pi+(-1)^{n} \frac{\pi}{4}, n \in Z\)
  4. D \(2 \mathrm{n} \pi \pm \frac{\pi}{2}, \mathrm{n} \in \mathrm{Z}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \mathrm{n} \pi \pm \frac{\pi}{2}, \mathrm{n} \in \mathrm{Z}\)

Step-by-step Solution

Detailed explanation

Given, \(\sin 2 x=4 \cos x\)
\[
\begin{aligned}
&\Rightarrow \quad 2 \sin x \cos x=4 \cos x \\
&\Rightarrow \quad 2 \cos x(\sin x-2)=0
\end{aligned}
\]
\(\Rightarrow \sin x=2\), which is not possible because the value of \(\sin x\) lies between \(-1\) and 1 .
\(\therefore \quad \cos \mathrm{x}=0\)
\(\Rightarrow \quad x=2 n \pi \pm \frac{\pi}{2}\)