KCET · Maths · Area Under Curves
The area of the region bounded by the curve \(y=x^2\) and the line \(y=16\) is
- A \(\frac{32}{3}\) sq. units
- B \(\frac{256}{3}\) sq. units
- C \(\frac{64}{3}\) sq. units
- D \(\frac{128}{3}\) sq. units
Answer & Solution
Correct Answer
(B) \(\frac{256}{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(y=x^2, y=16\)
\(\begin{aligned} & 2 \int_0^{16} \sqrt{y} d y=2 \frac{y^{3 / 2}}{3 / 2} \\ & =\frac{4}{3}\left(4^3\right)=\frac{256}{3}\end{aligned}\)

\(\begin{aligned} & 2 \int_0^{16} \sqrt{y} d y=2 \frac{y^{3 / 2}}{3 / 2} \\ & =\frac{4}{3}\left(4^3\right)=\frac{256}{3}\end{aligned}\)

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