KCET · Maths · Application of Derivatives
Suppose \( f(x)=(x+1)^{2} \) for \( x \geq-1 \). If \( g(x) \) is a function whose graph is the reflection of the
graph of \( f(x) \) in the line \( y=x \), then \( g(x)= \)
- A \( 0-\sqrt{x}-1 \)
- B \( \sqrt{x}-1 \)
- C \( \frac{1}{(x+1)^{2}} x>-1 \)
- D \( \sqrt{x}+1 \)
Answer & Solution
Correct Answer
(B) \( \sqrt{x}-1 \)
Step-by-step Solution
Detailed explanation
Given that \(f(x)=(x+1)^{2}\) for \(x \geq-1\) and \(g(x)\) is the reflexion of \(f(x)\) in the line \(y=x\), then \(g(x)\) is the inverse of \(f(x)\)
Let \(y=(x+1)^{2} \Rightarrow \sqrt{y}=x+1\)
\(x=\sqrt{y}-1\)
Now, \(f^{-1}(y)=\sqrt{y}-1\)
or \(g(x)=\sqrt{x}-1\)
Hence, the required function, \(g(x)=\sqrt{x}-1\)
Let \(y=(x+1)^{2} \Rightarrow \sqrt{y}=x+1\)
\(x=\sqrt{y}-1\)
Now, \(f^{-1}(y)=\sqrt{y}-1\)
or \(g(x)=\sqrt{x}-1\)
Hence, the required function, \(g(x)=\sqrt{x}-1\)
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