KCET · Maths · Functions
The shaded region shown in fig. is given by the inequation

- A \( 14 x+5 y \geq 70 ; y \leq 14 \) and \( x-y \leq 5 \)
- B \( 14 x+5 y \geq 70 ; y \leq 14 \) and \( x-y \geq 5 \)
- C \( 14 x+5 y \leq 70 ; y \leq 14 \) and \( x-y \geq 5 \)
- D \( 14 x+5 y \geq 70 ; y \geq 14 \) and \( x-y \geq 5 \)
Answer & Solution
Correct Answer
(A) \( 14 x+5 y \geq 70 ; y \leq 14 \) and \( x-y \leq 5 \)
Step-by-step Solution
Detailed explanation
Let points, \(A(0,14), B(5,0)\) and \(C(19,14)\)
Now, equation of side \(\mathrm{AB}\) is \(\frac{x}{5}+\frac{y}{14}=1\) \(\Rightarrow 14 x+5 y=70 \rightarrow(1)\) Equation of side \(\mathrm{AC}\) is \(y=14 \rightarrow(2)\) and equation of side \(\mathrm{BC}\) is \(x-y=5 \rightarrow(3)\) Therefore, the shaded region shown in figure is given by the inequation \(14 x+5 y>70 y < 14\) and \(x-y < 5\)
Now, equation of side \(\mathrm{AB}\) is \(\frac{x}{5}+\frac{y}{14}=1\) \(\Rightarrow 14 x+5 y=70 \rightarrow(1)\) Equation of side \(\mathrm{AC}\) is \(y=14 \rightarrow(2)\) and equation of side \(\mathrm{BC}\) is \(x-y=5 \rightarrow(3)\) Therefore, the shaded region shown in figure is given by the inequation \(14 x+5 y>70 y < 14\) and \(x-y < 5\)See the Complete Solution
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