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KCET · Maths · Limits

If \(\lim _{x \rightarrow 0} \frac{\sin (2+x)-\sin (2-x)}{x}=A \cos B\), then the values of \(A\) and \(B\) respectively are

  1. A 1,2
  2. B 2,1
  3. C 1,1
  4. D 2,2
Verified Solution

Answer & Solution

Correct Answer

(D) 2,2

Step-by-step Solution

Detailed explanation

We have,
\(\lim _{x \rightarrow 0} \frac{\sin (2+x)-\sin (2-x)}{x}=A \cos B\)
\(\lim _{x \rightarrow 0} \frac{2 \cos \left(\frac{2+x+2-x}{2}\right) \sin \left(\frac{2+x-2+x}{2}\right)}{x}\)
\(\begin{aligned} & =\lim _{x \rightarrow 0} 2 \cos 2 \frac{\sin x}{x} \\ & =2 \cos 2 \lim _{x \rightarrow 0} \frac{\sin x}{x}=2 \cos 2\end{aligned}\)
Thus, \(A=2\) and \(B=2\)