KCET · Maths · Circle
If the function \( f(x) \) defined by
\[
f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\ldots \ldots+\frac{x^{2}}{2}+x+1, \text { then } f^{\prime}(0)=
\]
- A \( 100 \)
- B \( -1 \)
- C \( 100 f^{\prime}(0) \)
- D \( 1 \)
Answer & Solution
Correct Answer
(D) \( 1 \)
Step-by-step Solution
Detailed explanation
Given that,
\( f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\cdot s+\frac{x^{2}}{2}+x+1 \)
here \( f^{\prime}(x)=1+x+x^{2}+\ldots .+x^{99} \)
Therefore, \( f(0)=1 \)
\( f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\cdot s+\frac{x^{2}}{2}+x+1 \)
here \( f^{\prime}(x)=1+x+x^{2}+\ldots .+x^{99} \)
Therefore, \( f(0)=1 \)
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