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KCET · Maths · Complex Number

If \(1, \omega, \omega^{2}\) are the cube roots of unity, then \((1+\omega)\left(1+\omega^{2}\right)\left(1+\omega^{4}\right)\left(1+\omega^{8}\right)\) is equal to

  1. A 1
  2. B 0
  3. C \(\omega^{2}\)
  4. D \(\omega\)
Verified Solution

Answer & Solution

Correct Answer

(A) 1

Step-by-step Solution

Detailed explanation

Given, \((1+\omega)\left(1+\omega^{2}\right)\left(1+\omega^{4}\right)\left(1+\omega^{8}\right)\)
\[
\begin{aligned}
&=(1+\omega)(-\omega)\left(1+\omega^{3} \cdot \omega\right)\left\{1+\left(\omega^{3}\right)^{2} \cdot \omega^{2}\right\} \\
&=(1+\omega)(-\omega)(1+\omega)\left(1+\omega^{2}\right) \quad\left[\because \omega^{2}=1\right] \\
&=(1+\omega)^{2}\left(-\omega-\omega^{3}\right) \quad \\
&=\left(1+\omega^{2}+2 \omega\right)(-\omega-1) \\
&=(-\omega+2 \omega)\left(+\omega^{2}\right)=\omega^{3}=1
\end{aligned}
\]