KCET · Maths · Functions
\( f: R \rightarrow R \) and \( g:[0, \infty) \rightarrow R \) is defined by \( f(x)=x^{2} \) and \( g(x)=\sqrt{x} \). Which one of the following is
not true?
- A fo \( g(-4)=4 \)
- B g of \( (-2)=2 \)
- C \( g \circ f(4)=4 \)
- D fo \( g(2)=2 \)
Answer & Solution
Correct Answer
(A) fo \( g(-4)=4 \)
Step-by-step Solution
Detailed explanation
(A)
\( f(x)=x^{2} g(x)=\sqrt{x} \)
fo \( g(-4)=f[g(-4)] \) is not defined
\( f(x)=x^{2} g(x)=\sqrt{x} \)
fo \( g(-4)=f[g(-4)] \) is not defined
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