KCET · Maths · Indefinite Integration
\(\int \frac{\sin \frac{5 x}{2}}{\sin \frac{x}{2}} d x\) is
- A \(2 x+\sin x+2 \sin 2 x+C\)
- B \(x+2 \sin x+2 \sin 2 x+C\)
- C \(x+2 \sin x+\sin 2 x+C\)
- D \(2 x+\sin x+\sin 2 x+C\)
Answer & Solution
Correct Answer
(C) \(x+2 \sin x+\sin 2 x+C\)
Step-by-step Solution
Detailed explanation
\(I=\int \frac{\sin \left(\frac{5 x}{2}\right)}{\sin \left(\frac{x}{2}\right)} d x\)
\(=\int \frac{2 \sin \left(\frac{5 x}{2}\right) \cos \left(\frac{x}{2}\right)}{\sin x} d x=\int \frac{\sin 3 x+\sin 2 x}{\sin x} d x\)
\(=\int \frac{\left(3 \sin x-4 \sin ^3 x\right)+2 \sin x \cos x}{\sin x} d x\)
\(=\int\left(3-4 \sin ^2 x+2 \cos x\right) d x\)
\(=\int(3-2(1-\cos 2 x)+2 \cos x) d x\)
\(=\int(3-2+2 \cos 2 x+2 \cos x) d x\)
\(=\int(1+2 \cos 2 x+2 \cos x) d x\)
\(=x+\sin 2 x+2 \sin x+C\)
\(=\int \frac{2 \sin \left(\frac{5 x}{2}\right) \cos \left(\frac{x}{2}\right)}{\sin x} d x=\int \frac{\sin 3 x+\sin 2 x}{\sin x} d x\)
\(=\int \frac{\left(3 \sin x-4 \sin ^3 x\right)+2 \sin x \cos x}{\sin x} d x\)
\(=\int\left(3-4 \sin ^2 x+2 \cos x\right) d x\)
\(=\int(3-2(1-\cos 2 x)+2 \cos x) d x\)
\(=\int(3-2+2 \cos 2 x+2 \cos x) d x\)
\(=\int(1+2 \cos 2 x+2 \cos x) d x\)
\(=x+\sin 2 x+2 \sin x+C\)
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