KCET · Chemistry · d and f Block Elements
Which one of the following shows highest magnetic moment?
- A \(\mathrm{Fe}^{2+}\)
- B \(\mathrm{Co}^{2+}\)
- C \(\mathrm{Cr}^{3+}\)
- D \(\mathrm{Ni}^{2+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Fe}^{2+}\)
Step-by-step Solution
Detailed explanation
The paramagnetism or magnetic moment produced due to spin of electrons or unpaired electrons is expressed in terms of Bohr magneton (BM) or \(\mu_{B}\) and given by
Magnetic moment \((\mu)=\sqrt{[n(n+2)]} \mathrm{BM}\)
where \(n\) is the number of unpaired electrons, in species. Thus, greater is the number of unpaired electrons in an ion greater is its paramagnetic nature.
As \(\mathrm{Fe}^{2+}\) ion has maximum number of unpaired electrons, thus it has highest magnetic moment.
Magnetic moment \((\mu)=\sqrt{[n(n+2)]} \mathrm{BM}\)
where \(n\) is the number of unpaired electrons, in species. Thus, greater is the number of unpaired electrons in an ion greater is its paramagnetic nature.
As \(\mathrm{Fe}^{2+}\) ion has maximum number of unpaired electrons, thus it has highest magnetic moment.
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