KCET · Chemistry · Chemical Kinetics
In the given graph, \(\mathrm{E}_{\mathrm{a}}\) for the reverse reaction will be

- A 125 KJ
- B 215 KJ
- C 90 KJ
- D 305 KJ
Answer & Solution
Correct Answer
(A) 125 KJ
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta H=\left(E_a\right)_f-\left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}} \\ & 90=215-\left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}} \\ & \left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}}=215-90=125 \mathrm{KJ}\end{aligned}\)
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