KCET · Chemistry · Chemical Equilibrium
The relationship between \( \mathrm{K}_{\mathrm{p}} \) and \( \mathrm{K}_{\mathrm{c}} \) is \( \mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}} \) (RT) \( ^{\Delta n_{g}} \). What would be the value of \( \Delta n_{g} \) for
the reaction
\( \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{s}) \rightleftharpoons \mathrm{NH}_{3}(\mathrm{~g})+\mathrm{HCl}(\mathrm{g}) ? \)
- A \( 11 \)
- B \( 0.5 \)
- C \( 1.5 \)
- D \( 12 \)
Answer & Solution
Correct Answer
(D) \( 12 \)
Step-by-step Solution
Detailed explanation
We know
\(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta n_{g}}\)
\(\Delta n_{g}=\) no. of moles of products in gaseous phase
- no. of moles of reactants in gaseous phase.
For the given reaction
\(N H_{4} C l(S) \rightleftharpoons N H_{3}(g)+H C l(g)\)
\(\Delta n_{g}=2-0=2\)
Therefore,
\(K_{p}=K_{c}(R T)^{0}\) or \(K_{p}=K_{c}\)
\(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta n_{g}}\)
\(\Delta n_{g}=\) no. of moles of products in gaseous phase
- no. of moles of reactants in gaseous phase.
For the given reaction
\(N H_{4} C l(S) \rightleftharpoons N H_{3}(g)+H C l(g)\)
\(\Delta n_{g}=2-0=2\)
Therefore,
\(K_{p}=K_{c}(R T)^{0}\) or \(K_{p}=K_{c}\)
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