KCET · Chemistry · Solid State
A metal crystallises in face centred cubic structure with metallic radius \(\sqrt{2} Å\). The volume of the unit cell (in \(\mathrm{m}^{3}\) ) is
- A \(4 \times 10^{-10}\)
- B \(6.4 \times 10^{-29}\)
- C \(4 \times 10^{-9}\)
- D \(6.4 \times 10^{-30}\)
Answer & Solution
Correct Answer
(B) \(6.4 \times 10^{-29}\)
Step-by-step Solution
Detailed explanation
In fcc, \(4 r=\sqrt{2} a\)
\(\begin{aligned}
\text { Volume of unit cell } &=a^{3}=\left(\frac{4 r}{\sqrt{2}}\right)^{3}=\frac{64}{2 \sqrt{2}} \times(\sqrt{2})^{3} Å \\
&=\frac{64}{2 \sqrt{2}} \times 2 \sqrt{2} Å \\
&=64 \times 10^{-30} \mathrm{~m}^{3} \\
&=6.4 \times 10^{-29} \mathrm{~m}^{3}
\end{aligned}\)
\(\begin{aligned}
\text { Volume of unit cell } &=a^{3}=\left(\frac{4 r}{\sqrt{2}}\right)^{3}=\frac{64}{2 \sqrt{2}} \times(\sqrt{2})^{3} Å \\
&=\frac{64}{2 \sqrt{2}} \times 2 \sqrt{2} Å \\
&=64 \times 10^{-30} \mathrm{~m}^{3} \\
&=6.4 \times 10^{-29} \mathrm{~m}^{3}
\end{aligned}\)
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