KCET · Chemistry · Thermodynamics (C)
The amount of heat evolved when \(500 \mathrm{~cm}^{3}\) of
\(0.1 \mathrm{M} \mathrm{HCl}\) is mixed with \(200 \mathrm{~cm}^{3}\) of \(0.2 \mathrm{M}\) \(\mathrm{NaOH}\) is
- A \(2.292 \mathrm{~kJ}\)
- B \(1.292 \mathrm{~kJ}\)
- C \(22.9 \mathrm{~kJ}\)
- D \(0.292 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(2.292 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
No. of equivalents of \(\mathrm{NaOH}\) reacting \(=\frac{40}{1000}\)
\[
\begin{gathered}
1 \mathrm{eq}=57.3 \\
\frac{40}{1000} \mathrm{eq}=\frac{57.3 \times 40}{1000}=2.292 \mathrm{~kJ}
\end{gathered}
\]
\[
\begin{gathered}
1 \mathrm{eq}=57.3 \\
\frac{40}{1000} \mathrm{eq}=\frac{57.3 \times 40}{1000}=2.292 \mathrm{~kJ}
\end{gathered}
\]
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