KCET · Chemistry · s Block Elements
The pair of compound which cannot exist together in solution is
- A \( \mathrm{NaHCO}_{3} \) and \( \mathrm{N} a \mathrm{OH} \)
- B \( \mathrm{NaHCO}_{3} \) and \( \mathrm{H}_{2} \mathrm{O} \)
- C \( \mathrm{NaHCO}_{3} \) and \( \mathrm{N} a_{2} \mathrm{CO}_{3} \)
- D \( \mathrm{Na}_{2} \mathrm{CO}_{3} \) and \( \mathrm{NaOH} \)
Answer & Solution
Correct Answer
(A) \( \mathrm{NaHCO}_{3} \) and \( \mathrm{N} a \mathrm{OH} \)
Step-by-step Solution
Detailed explanation
\( \mathrm{NaHCO}_{3} \) is unstable with \( \mathrm{NaOH} \), because \( \mathrm{NaHCO}_{3} \) is a basic salt, therefore, will react with \( \mathrm{NaOH} \) and form
\( \mathrm{Na}_{2} \mathrm{CO}_{3} \) and water
\( \mathrm{NaHCO}_{3}+\mathrm{NaOH} \rightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O} \)
\( \mathrm{Na}_{2} \mathrm{CO}_{3} \) and water
\( \mathrm{NaHCO}_{3}+\mathrm{NaOH} \rightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O} \)
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