KCET · Chemistry · Alcohols Phenols and Ethers
The pair of compounds having identical shapes for their molecules is
- A \( \mathrm{BCl}_{2}, \mathrm{ClF}_{3} \)
- B \( \mathrm{SO}_{2}, \mathrm{CO}_{2} \)
- C \( \mathrm{CH}_{4}, \mathrm{SF}_{4} \)
- D None of the above
Answer & Solution
Correct Answer
(D) None of the above
Step-by-step Solution
Detailed explanation
Hybridization of \( \mathrm{Xe} \) in \( \mathrm{XeF}_{2} \) molecule is \( p^{3} d \) Three lone pair of electrons occupies the equatorial position and two \( \mathrm{F} \)
atoms occupies axial position therefore; its shape is linear \( \mathrm{ZnCl}_{2} \) is an ionic compound. So, non of the pair have
identical shape.
atoms occupies axial position therefore; its shape is linear \( \mathrm{ZnCl}_{2} \) is an ionic compound. So, non of the pair have
identical shape.
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