KCET · Chemistry · Chemical Bonding and Molecular Structure
The overlapping of orbitals in benzene is of the type
- A sp-sp
- B sp2-sp3
- C \(\mathrm{sp}^{2}-\mathrm{sp}^{2}\)
- D \(\mathrm{sp}^{3}-\mathrm{sp}^{3}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{sp}^{2}-\mathrm{sp}^{2}\)
Step-by-step Solution
Detailed explanation
The molecular orbital picture of benzene shows that in it all the six carbon atoms are \(\mathrm{sp}^{2}\) hybridised. Out of these three \({s p^{2}}^{2}\) hybrid orbitals of each C atom, two orbitals overlap with \(\mathrm{sp}^{2}\) hybrid orbitals of adjacent \(C\) atoms to form six \(\mathrm{C}-\mathrm{C}\) single bonds. The remaining \(\mathrm{sp}^{2}\) orbital of each \(C\) atom overlaps with -orbital of each hydrogen atom to form six \(\mathrm{C}-\mathrm{H}\) single sigma bonds. Each C atom is now left with one unhybridised -orbital perpendicular to the plane of the ring.
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