KCET · Chemistry · Coordination Compounds
The oxidation state of iron in \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) is
- A 1
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
Let the oxidation state of iron in \(\mathrm{K}_{4}\left[\mathrm{Fe}\left(\mathrm{CN}_{6}\right]\right.\) is \(x\)
\(\begin{aligned} 4(+1)+x+6(-1) &=0 \\ 4+x-6 &=0 \\ x &=+2 \\ \mathrm{Au}+8 \mathrm{CN}^{-}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2} \longrightarrow & \underset{\text { Soluble }}{\longrightarrow} \\ 2\left[\mathrm{Au}(\mathrm{CN})_{2} \Gamma+\mathrm{Zn} \longrightarrow\right.& \mathrm{Au}(s) \downarrow+\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-} \end{aligned}\)
\(\begin{aligned} 4(+1)+x+6(-1) &=0 \\ 4+x-6 &=0 \\ x &=+2 \\ \mathrm{Au}+8 \mathrm{CN}^{-}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2} \longrightarrow & \underset{\text { Soluble }}{\longrightarrow} \\ 2\left[\mathrm{Au}(\mathrm{CN})_{2} \Gamma+\mathrm{Zn} \longrightarrow\right.& \mathrm{Au}(s) \downarrow+\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-} \end{aligned}\)
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