KCET · Chemistry · Chemical Bonding and Molecular Structure
The number of anti-bonding electrons present in \(\mathrm{O}_{2}^{-}\)molecular ion is
- A 8
- B 6
- C 5
- D 4
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
\(\mathrm{MO}\) configuration of \(\mathrm{O}_{2}^{+}\)molecular ion :
\(\sigma 1 s^{2}, \sigma^{*} s^{2}, \sigma 2 s^{2}, \overbrace{}^{*} 2 s^{2}, \sigma 2 p_{x}^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}, \stackrel{*}{\pi} 2 p_{y}^{1}\)
Hence, number of antibonding electrons
\(=2(1 s)+2(2 s)+1(2 p)=5\)
\(\sigma 1 s^{2}, \sigma^{*} s^{2}, \sigma 2 s^{2}, \overbrace{}^{*} 2 s^{2}, \sigma 2 p_{x}^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}, \stackrel{*}{\pi} 2 p_{y}^{1}\)
Hence, number of antibonding electrons
\(=2(1 s)+2(2 s)+1(2 p)=5\)
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