KCET · Chemistry · d and f Block Elements
The incorrect statement in respect of chromyl chloride test is
- A formation of red vapours
- B formation of lead chromate
- C formation of chromyl chloride
- D liberation of chlorine
Answer & Solution
Correct Answer
(D) liberation of chlorine
Step-by-step Solution
Detailed explanation
Chromyl chloride test is used for \(\mathrm{Cl}^{-}\)ions. Chlorine is not liberated in this test.

\(\mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Na}_{2} \mathrm{CrO}_{4}+2 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Na}_{2} \mathrm{CrO}_{4}+\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \longrightarrow 2 \mathrm{CH}_{3} \mathrm{COONa}+\underset{\text { lead chromate }}{\mathrm{PbCrO}_{4}}\)

\(\mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Na}_{2} \mathrm{CrO}_{4}+2 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Na}_{2} \mathrm{CrO}_{4}+\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \longrightarrow 2 \mathrm{CH}_{3} \mathrm{COONa}+\underset{\text { lead chromate }}{\mathrm{PbCrO}_{4}}\)
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