KCET · Chemistry · Structure of Atom
The correct set of four quantum numbers for outermost electron of potassium \((Z=19)\) is
- A \(4,1,0, \frac{1}{2}\)
- B \(3,1,0, \frac{1}{2}\)
- C \(4,0,0, \frac{1}{2}\)
- D \(3,0,0, \frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(4,0,0, \frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}(19): 1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2} 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{1}\)
\(4 s^{1}\) is the valence electron in potassium, hence the correct set of four quantum numbers for outermost electron is \(4,0,0, \frac{1}{2}\).
\(4 s^{1}\) is the valence electron in potassium, hence the correct set of four quantum numbers for outermost electron is \(4,0,0, \frac{1}{2}\).
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