KCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Excess of \(\mathrm{PCl}_{5}\) reacts with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) giving
- A chlorosulphuric acid
- B sulphurous acid
- C sulphury chloride
- D thionyl chloride
Answer & Solution
Correct Answer
(C) sulphury chloride
Step-by-step Solution
Detailed explanation
\(\mathrm{PCl}_{5}\) reacts with \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and replaces the hydroxyl groups by chlorine atoms.
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