KCET · Chemistry · Structure of Atom
If the energies of the two photons in the ratio of \(3: 2\), their wavelength will be in the ratio of
- A \(2: 3\)
- B \(9: 4\)
- C \(3: 2\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(A) \(2: 3\)
Step-by-step Solution
Detailed explanation
\(E_{1}: E_{2}=\frac{h c}{\lambda_{1}}: \frac{h c}{\lambda_{2}}=\frac{1}{\lambda_{1}}: \frac{1}{\lambda_{2}}\) \(3: 2=\frac{1}{\lambda_{1}}: \frac{1}{\lambda_{2}}=\frac{\lambda_{2}: \lambda_{1}}{\lambda_{1} \lambda_{2}}\) \(\therefore \quad \lambda_{2}: \lambda_{1}=3: 2\) or \(\lambda_{1}: \lambda_{2}=2: 3\)
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