KCET · Chemistry · Haloalkanes and Haloarenes
The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with
- A \(\mathrm{PCl}_{3}\)
- B \(\mathrm{PCl}_{5}\)
- C \(\mathrm{SOCl}_{2}\) in presence of pyridine
- D dry \(\mathrm{HCl}\) in the presence of anhydrous \(\mathrm{ZnCl}_{2}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{SOCl}_{2}\) in presence of pyridine
Step-by-step Solution
Detailed explanation
The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with \(\mathrm{SOCl}_{2}\) in the presence of pyridine.
\[
\mathrm{ROH}+\mathrm{SOCl}_{2} \longrightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{SO}_{2}
\]
The other products being gases escape leaving behind pure alkyl halide.
\[
\mathrm{ROH}+\mathrm{SOCl}_{2} \longrightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{SO}_{2}
\]
The other products being gases escape leaving behind pure alkyl halide.
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