KCET · Chemistry · Coordination Compounds
The atomic number of cobalt is 27. The EAN of cobalt in \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{4} \mathrm{Cl}_{2}\right]\) is
- A 24
- B 36
- C 34
- D 35
Answer & Solution
Correct Answer
(B) 36
Step-by-step Solution
Detailed explanation
EAN of \(\mathrm{Co}\) in \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{4} \mathrm{Cl}_{2}\right]\)
= Atomic number of Co \(\pm\) oxidation state of Co
+ number of \(\mathrm{e}^{-}\)taken from \(-\mathrm{NO}_{2}\) and \(-\mathrm{Cl}\)
\[
=27+3+(4+2)=36
\]
= Atomic number of Co \(\pm\) oxidation state of Co
+ number of \(\mathrm{e}^{-}\)taken from \(-\mathrm{NO}_{2}\) and \(-\mathrm{Cl}\)
\[
=27+3+(4+2)=36
\]
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