KCET · Chemistry · Structure of Atom
The last element of the \(p\)-block in 6th period is represented by the outer most electronic configuration.
- A \(7 s^{2}, 7 p^{6}\),
- B \(5 f^{14} 6 d{ }^{10} 7 s^{2}, 7 p^{5}\)
- C \(4 f^{14}, 5 d^{10}, 6 s^{2}, 6 p^{4}\)
- D \(4 f,{ }^{14} 5 d,^{10} 6 s^{2}, 6 p^{6}\)
Answer & Solution
Correct Answer
(D) \(4 f,{ }^{14} 5 d,^{10} 6 s^{2}, 6 p^{6}\)
Step-by-step Solution
Detailed explanation
The last element in the sixth period will be noble gas Rn with atomic number 86 and electronic configuration \(4 f^{14}, 5 d^{10}, 6 s^{2}, 6 p^{6}\).
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