KCET · Chemistry · Chemical Bonding and Molecular Structure
The arrangement of following compounds :
i. bromomethane
ii. bromofonn
iii. chloromethane
iv. dibromomethane
In the increasing order of their boiling point is
- A iii \( < i < i v < i \)
- B iv \( < \mathrm{iii} < \mathrm{i} < \mathrm{i} \)
- C \( \mathrm{ii} < \mathrm{iii} < \mathrm{i} < \mathrm{iv} \)
- D \( \mathrm{i} < \mathrm{ii} < \mathrm{iii} < \mathrm{iv} \)
Answer & Solution
Correct Answer
(A) iii \( < i < i v < i \)
Step-by-step Solution
Detailed explanation
The intermolecular forces of attraction become stronger with the increase in size of the molecules. Hence, the order of
boiling points will be
\( \mathrm{CH}_{3} \mathrm{Cl} < \mathrm{CH}_{3} \mathrm{Br} < \mathrm{CH}_{3} \mathrm{Br}_{2} < \mathrm{CH} \mathrm{Br}_{3} \)
boiling points will be
\( \mathrm{CH}_{3} \mathrm{Cl} < \mathrm{CH}_{3} \mathrm{Br} < \mathrm{CH}_{3} \mathrm{Br}_{2} < \mathrm{CH} \mathrm{Br}_{3} \)
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