KCET · Chemistry · Some Basic Concepts of Chemistry
A mixture of \(\mathrm{CaCl}_{2}\) and \(\mathrm{NaCl}\) weighing \(4.44 \mathrm{~g}\) is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get \(0.56 \mathrm{~g}\) of \(\mathrm{CaO}\). The percentage of \(\mathrm{NaCl}\) in the mixture is (atomic mass of \(\mathrm{Ca}=40\) )
- A 75
- B \(31.5\)
- C \(40.2\)
- D 25
Answer & Solution
Correct Answer
(A) 75
Step-by-step Solution
Detailed explanation
\(\therefore\) Amount of \(\mathrm{NaCl}=4.44-1.12=3.32\)
\(\%\) of \(\mathrm{NaCl}=\frac{3.32}{4.44} \times 100=75\)
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