KCET · Chemistry · General Organic Chemistry
Meso compounds do not show optical activity because
- A they do not contain chiral carbon atoms
- B they have non-superimposable mirror images
- C they contain plane of symmetry
- D they do not contain plane of symmetry
Answer & Solution
Correct Answer
(C) they contain plane of symmetry
Step-by-step Solution
Detailed explanation
Meso compounds are those compounds whose molecules are superimposable on their mirror images inspite of the presence of an asymmetric carbon atom. This is due to internal compensation. The two halves of the molecule rotate the plane of polarised light in opposite direction and hence cancel the effect of each other and make the molecule optically inactive.

Thus, the optical inactivity in meso compounds are because of plane of symmetry or molecular symmetry or internal compensation.

Thus, the optical inactivity in meso compounds are because of plane of symmetry or molecular symmetry or internal compensation.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- The test to differentiate between pentan-2-one and pentan-3-one isKCET 2022 Medium
- The correct order of increasing basic nature forthe bases \( \mathrm{NH}_{3}, \mathrm{CH}_{3} \mathrm{NH}_{2} \) and \( \left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} \)
inaqueous solutionsKCET 2017 Medium - Paracetamol is a/anKCET 2007 Medium
- The rate equation for a reaction \(\mathrm{A} \rightarrow \mathrm{B}\) is \(\mathrm{r}=\mathrm{k}[\mathrm{A}]^{0}\). If the initial concentration of the reactant is \(a \mathrm{~mol} \mathrm{dm}{ }^{-3}\), the half-life period of the reaction isKCET 2009 Easy
- The vapour pressures of two liquids \(A\) and \(B\) in their pure states are in the ratio of \(1: 2\). A binary solution of \(A\) and \(B\) contains \(A\) and \(B\) in the mole proportion of \(1: 2\). The mole fraction of \(A\) in the vapour phase of the solution will beKCET 2012 Easy
- \( 3 \mathrm{~A} \rightarrow 2 \mathrm{~B} \), rate of reaction \( +\frac{d[B]}{d t} \) is equal toKCET 2016 Easy
More PYQs from KCET
- If \( \left[\begin{array}{cc}1 & 1 \\ -1 & 1\end{array}\right]\left[\begin{array}{l}\mathrm{x} \\ \mathrm{y}\end{array}\right]=\left[\begin{array}{c}2 \\ 4\end{array}\right] \), then the values of \( \mathrm{x} \) and \( \mathrm{y} \) respectively areKCET 2018 Easy
- Match the storage products listed under Column-I with the organisms given under Column-II. Choose the appropriate option from the given choices.
Column I Column II A. Glycogen p. Sargassum B. Pyrenoids q. Nostoc C. Laminarin and mannitol r. Polysiphonia D. Floridean starch s. Spirogyra t. Agaricus KCET 2014 Hard - \(\sum\limits_{n=1}^{4} (-1)^{2n} \cdot i^{2n} = \)KCET 2026 Easy
- In which of the tRNA molecules is the amino acid binding site located?KCET 2021 Easy
- The function \(f(x)=x^{2}-2 x\) is strictly decreasing in the intervalKCET 2021 Easy
- Let \(f: R \rightarrow R\) be given \(f(x)=\tan x\). Then, \(f^{-1}(1)\) isKCET 2024 Easy