KCET · Chemistry · Thermodynamics (C)
Lattice enthalpy for \(\mathrm{NaCl}\) is \(+788 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(\Delta H_{\text {hyd }}^{\circ}=-784 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Enthalpy of solution of \(\mathrm{NaCl}\) is
- A \(+572 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- B \(+4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(-572 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(-4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(+4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Delta H_{\text {sol }}=\Delta H_{\text {lattice }}+\Delta H_{\text {hydration }}\)
\(=788+(-784)=4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(=788+(-784)=4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
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