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KCET · Chemistry · Carboxylic Acid Derivatives

\( 25 \mathrm{~cm}^{3} \) of oxalic acid completely neutralized \( 0.064 \mathrm{~g} \) of sodium hydroxide. Molarity of the
oxalic acid solution is

  1. A \( 0.045 \)
  2. B \( 0.032 \)
  3. C \( 0.064 \)
  4. D \( 0.015 \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 0.032 \)

Step-by-step Solution

Detailed explanation

Given,
\(V\) (oxalic acid) \(=25 \mathrm{~cm}^{3}\)
\(W(N a O H)=0.064 g\)
\(M\) (oxalic acid) \(=?\)
Since, moles of oxalic acid \(=\) mole of \(N a O H\)
\(V\) (oxalic acid) \(\times N\) (oxalic acid) \(=\frac{w}{M}(N a O H)\)
\(\Rightarrow N\) ( oxalic acid) \(=\frac{0.064 \times 1000}{25 \times 40}=0.064\)
Normality \(=\) Molarity \(\times\) Basicity
\(\Rightarrow\) Molarity \(=\frac{0.064}{2}=0.32\)
Note: Basicity of oxalic acid is 2