KCET · Chemistry · Solid State
The number of atoms in \( 2.4 \mathrm{~g} \) of body centred cubic crystal with edge length \( 200 \mathrm{pm} \) is (density
\( =10 \mathrm{~g} \mathrm{~cm}^{-3}, \mathrm{NA}=6 \times 10^{23} \) atoms \( / \mathrm{mol} \) )
- A \( 6 \times 10^{23} \)
- B \( 6 \times 10^{19} \)
- C \( 6 \times 10^{22} \)
- D \( 6 \times 10^{20} \)
Answer & Solution
Correct Answer
(C) \( 6 \times 10^{22} \)
Step-by-step Solution
Detailed explanation
\(d=\frac{Z M}{a^{3} N_{A}}\)
\(M=\frac{d \times a^{3} \times N_{A}}{Z}=\frac{10 \times(200)^{3} \times 10^{-30} \times 6 \times 10^{23}}{2}=24\)
\(24 \mathrm{~g}\) contains \(6 \times 10^{23}\)
\(2.4 \mathrm{~g}\) contains?
\(6 \times 10^{22}\)
\(M=\frac{d \times a^{3} \times N_{A}}{Z}=\frac{10 \times(200)^{3} \times 10^{-30} \times 6 \times 10^{23}}{2}=24\)
\(24 \mathrm{~g}\) contains \(6 \times 10^{23}\)
\(2.4 \mathrm{~g}\) contains?
\(6 \times 10^{22}\)
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