KCET · Chemistry · Chemical Kinetics
For the reaction, \( 2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3} \), the rate of disappearance of \( \mathrm{O}_{2} \) is
\( 2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \). The rate of apperance of \( \mathrm{SO}_{3} \) is
- A \( 2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
- B \( 4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
- C \( 1 \times 10^{-1} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
- D \( 6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
Answer & Solution
Correct Answer
(B) \( 4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
Step-by-step Solution
Detailed explanation
For the reaction,
\(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}\)
Rate
\(=-\frac{1}{2} \frac{d\left[\mathrm{SO}_{2}\right]}{d t}=-\frac{d\left[\mathrm{O}_{2}\right]}{d t}=+\frac{1}{2} \frac{d\left[\mathrm{SO}_{3}\right]}{d t}\)
Given \(-\frac{d\left[\mathrm{O}_{2}\right]}{d t}=2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
To find \(+\frac{d\left[\mathrm{SO}_{3}\right]}{d t}=?\)
\(+\frac{1}{2} \frac{d\left[\mathrm{SO}_{3}\right]}{d t}=-\frac{d\left[\mathrm{O}_{2}\right]}{d t}\)
\(\frac{d\left[\mathrm{SO}_{3}\right]}{d t}=2 \times 2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
\(=4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
\(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}\)
Rate
\(=-\frac{1}{2} \frac{d\left[\mathrm{SO}_{2}\right]}{d t}=-\frac{d\left[\mathrm{O}_{2}\right]}{d t}=+\frac{1}{2} \frac{d\left[\mathrm{SO}_{3}\right]}{d t}\)
Given \(-\frac{d\left[\mathrm{O}_{2}\right]}{d t}=2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
To find \(+\frac{d\left[\mathrm{SO}_{3}\right]}{d t}=?\)
\(+\frac{1}{2} \frac{d\left[\mathrm{SO}_{3}\right]}{d t}=-\frac{d\left[\mathrm{O}_{2}\right]}{d t}\)
\(\frac{d\left[\mathrm{SO}_{3}\right]}{d t}=2 \times 2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
\(=4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~S}^{-1}\)
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