KCET · Chemistry · Ionic Equilibrium
\(5 \mathrm{~mL}\) of \(0.4 \mathrm{~N} \mathrm{NaOH}\) is mixed with \(20 \mathrm{~mL}\) of \(0.1 \mathrm{~N} \mathrm{HCl}\). The \(\mathrm{pH}\) of the resulting solution will be
- A 7
- B 8
- C 5
- D 6
Answer & Solution
Correct Answer
(A) 7
Step-by-step Solution
Detailed explanation
From the first law of thermodynamics, the total energy of the universe remains constant.
\[
\begin{aligned}
&\text { Milliequivalents of } \mathrm{NaOH}=\mathrm{N}_{1} \mathrm{~V}_{1} \\
&\qquad=0.4 \times 5=0.20 \\
&\text { Milliequivalents of } \mathrm{HCl}=\mathrm{N}_{2} \mathrm{~V}_{2} \\
&\qquad=0.1 \times 20=0.20
\end{aligned}
\]
\[
\begin{aligned}
&\text { Milliequivalents of } \mathrm{NaOH}=\mathrm{N}_{1} \mathrm{~V}_{1} \\
&\qquad=0.4 \times 5=0.20 \\
&\text { Milliequivalents of } \mathrm{HCl}=\mathrm{N}_{2} \mathrm{~V}_{2} \\
&\qquad=0.1 \times 20=0.20
\end{aligned}
\]
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