KCET · Chemistry · Chemical Kinetics
For the decomposition of a compound \(A B\) at \(600 \mathrm{~K}\), the following data were obtained
The order for the decomposition of \(A B\) is
- A \(1.5\)
- B 0
- C 1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(\mathrm{AB} \longrightarrow\) Product
Rate \(=\mathrm{k}[\mathrm{AB}]^{\mathrm{n}}\)
(Rate) \()_{1}=\mathrm{k}[0.20]^{\mathrm{n}}=2.75 \times 10^{-8} \quad \text{...(i)}\)
(Rate) \({ }_{2}=\mathrm{k}[0.40]^{\mathrm{n}}=11.0 \times 10^{-8} \quad \text{...(ii)}\)
Dividing Eq. (ii) by Eq. (i),
\(\begin{array}{lrl} & 2^{\mathrm{n}} & =4 \\ \text { or } & 2^{\mathrm{n}} & =2^{2} \\ \text { Hence, } & \mathrm{n} & =2\end{array}\)
Rate \(=\mathrm{k}[\mathrm{AB}]^{\mathrm{n}}\)
(Rate) \()_{1}=\mathrm{k}[0.20]^{\mathrm{n}}=2.75 \times 10^{-8} \quad \text{...(i)}\)
(Rate) \({ }_{2}=\mathrm{k}[0.40]^{\mathrm{n}}=11.0 \times 10^{-8} \quad \text{...(ii)}\)
Dividing Eq. (ii) by Eq. (i),
\(\begin{array}{lrl} & 2^{\mathrm{n}} & =4 \\ \text { or } & 2^{\mathrm{n}} & =2^{2} \\ \text { Hence, } & \mathrm{n} & =2\end{array}\)
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