KCET · Chemistry · Coordination Compounds
Extraction of chlorine from brine solution is based on
- A Oxidation
- B Chlorination
- C Reduction
- D Acidification
Answer & Solution
Correct Answer
(A) Oxidation
Step-by-step Solution
Detailed explanation
Chloride is obtained by the electrolysis of brine solution (conc. NaCl solution). Chlorine is liberated at the anode the sodium metal is liberated at the cathode and reacts with water to form \(\mathrm{NaOH}\) and \(\mathrm{H}_{2}\)
At anode oxidation takes place:
\[
\begin{array}{l}
\mathrm{Cl}^{-} \rightarrow \mathrm{Cl}+e^{-} \\
\mathrm{Cl}+\mathrm{Cl} \rightarrow \mathrm{Cl}_{2}
\end{array}
\]
At cathode reduction takes place:
\(\mathrm{Na}^{+}+e^{-} \rightarrow \mathrm{Na}\) \(2 \mathrm{Na}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{~N} a \mathrm{OH}+\mathrm{H}_{2}\)
Therefore, extraction of chlorine from brine solution is based on oxidation.
At anode oxidation takes place:
\[
\begin{array}{l}
\mathrm{Cl}^{-} \rightarrow \mathrm{Cl}+e^{-} \\
\mathrm{Cl}+\mathrm{Cl} \rightarrow \mathrm{Cl}_{2}
\end{array}
\]
At cathode reduction takes place:
\(\mathrm{Na}^{+}+e^{-} \rightarrow \mathrm{Na}\) \(2 \mathrm{Na}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{~N} a \mathrm{OH}+\mathrm{H}_{2}\)
Therefore, extraction of chlorine from brine solution is based on oxidation.
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