KCET · Chemistry · p Block Elements (Group 13 & 14)
An alkali metal hydride \( (\mathrm{NaH}) \) reacts with diborane in ' \( A \) ' to give a tetrahedral compound 'ET
which is extensively used as reducing agent in organic synthesis. The compounds 'A' and 'ET
respectively are
- A \( C_{2} H_{6} \) and \( C_{2} H_{5} \mathrm{Na} \)
- B \( \mathrm{CH}_{3} \mathrm{COCH}_{3} \) and \( \mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6} \)
- C \( C_{6} H_{6} \) and \( \mathrm{NaBH}_{4} \)
- D \( \left(C_{2} H_{5}\right)_{2} O \) and \( \mathrm{NaBH}_{4} \)
Answer & Solution
Correct Answer
(D) \( \left(C_{2} H_{5}\right)_{2} O \) and \( \mathrm{NaBH}_{4} \)
Step-by-step Solution
Detailed explanation
The reaction involved is
\(2 N a H+B_{2} H_{6}^{(A)\left(C_{2} H_{5}\right)_{2} O}\) (B) \(2 N a B H_{4}\)
The compound (B) is sodium borohydride ( \( \mathrm{NaBH}_{4} \) ) which is a reducing agent in many organic syntheses.
\(2 N a H+B_{2} H_{6}^{(A)\left(C_{2} H_{5}\right)_{2} O}\) (B) \(2 N a B H_{4}\)
The compound (B) is sodium borohydride ( \( \mathrm{NaBH}_{4} \) ) which is a reducing agent in many organic syntheses.
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