KCET · Chemistry · Electrochemistry
During the electrolysis of brine, by using inert electrodes,
- A \(\mathrm{O}_2\) liberates at anode
- B \(\mathrm{H}_2\) liberates at anode
- C Na deposits on cathode
- D \(\mathrm{Cl}_2\) liberates at anode
Answer & Solution
Correct Answer
(D) \(\mathrm{Cl}_2\) liberates at anode
Step-by-step Solution
Detailed explanation
During electrolysis of brine using inert
electrodes.
At anode : \(2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2+2 e^{-}\)
At cathode : \(2 \mathrm{H}_2 \mathrm{O}+2 e^{-} \longrightarrow \mathrm{H}_2+2 \mathrm{OH}^{-}\)
Overall, \(2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Cl}_2+\mathrm{H}_2+2 \mathrm{NaOH}\)
i.e. \(\mathrm{Cl}_2\) is produced at anode while \(\mathrm{H}_2\) is produced at cathode.
electrodes.
At anode : \(2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2+2 e^{-}\)
At cathode : \(2 \mathrm{H}_2 \mathrm{O}+2 e^{-} \longrightarrow \mathrm{H}_2+2 \mathrm{OH}^{-}\)
Overall, \(2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Cl}_2+\mathrm{H}_2+2 \mathrm{NaOH}\)
i.e. \(\mathrm{Cl}_2\) is produced at anode while \(\mathrm{H}_2\) is produced at cathode.
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