KCET · Chemistry · Ionic Equilibrium
A weak acid with \(\mathrm{p} K_a 5.9\) and weak base with \(\mathrm{p} K_b 5.8\) are mixed in equal proportions. \(\mathrm{pH}\) of the resulting solution is
- A \(7.005\)
- B \(7.5\)
- C \(7\)
- D \(7.05\)
Answer & Solution
Correct Answer
(D) \(7.05\)
Step-by-step Solution
Detailed explanation
\(\mathrm{pH}\) of the resultant solution is given by,
\(\begin{aligned} \mathrm{pH} & =7+\frac{1}{2}\left(\mathrm{pK}_a-\mathrm{p} K_b\right)=7+\frac{1}{2}(5.9-5.8) \\ \mathrm{pH} & =7.05\end{aligned}\)
\(\begin{aligned} \mathrm{pH} & =7+\frac{1}{2}\left(\mathrm{pK}_a-\mathrm{p} K_b\right)=7+\frac{1}{2}(5.9-5.8) \\ \mathrm{pH} & =7.05\end{aligned}\)
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