An oxygen containing organic compound was found to contain \(52 \%\) carbon and \(13 \%\) of hydrogen. Its vapour density is 23 . The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is

\(\therefore\) Empirical formula of the compound \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) and empirical formula weight
\[
=2 \times 12+6 \times 1+16=46
\]
\(\because\) Molecular weight \(=2 \times\) vapour density
\(\therefore\) Molecular weight \(=2 \times 23=46\)
\(\therefore \quad \mathrm{n}=\frac{46}{46}=1\)
\(\therefore\) Molecular formula of the compound \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\)
\(\because\) Compound liberates \(\mathrm{H}_{2}\) with \(\mathrm{Na}\).
\(\because\) It must be alcohol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (ethanol)
Its functional isomer is \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\) (methoxy methane)