KCET · Chemistry · Alcohols Phenols and Ethers
8.8 g of monohydric alcohol added to ethyl magnesium iodide in ether liberates \(2240 \mathrm{~cm}^3\) of ethane at STP. This monohydric alcohol when oxidised using pyridinium-chloro-chromate, forms a carbonyl compound that answers silver mirror test (Tollen's test). The monohydric alcohol is
- A butan-2-ol
- B 2, 2-dimethyl propan-1-ol
- C pentan-2-ol
- D 2, 2-dimethyl ethan-1-ol
Answer & Solution
Correct Answer
(B) 2, 2-dimethyl propan-1-ol
Step-by-step Solution
Detailed explanation
Given that, 8.8 g of monohydric alcohol liberates \(2240 \mathrm{~cm}^3\) of ethane.
So, 88 g of monohydric alcohol will liberate \(22400 \mathrm{~cm}^3\) (STP)
Now, the carbonyl compound that can oxidise Tollens reagent is aldehyde and it is the oxidising product of \(1^{\circ}\) alcohol. So, among the given options 2, 2-dimethyl propan-1-ol (molecular mass \(=88\) ) is the required monohydric alcohol.
So, 88 g of monohydric alcohol will liberate \(22400 \mathrm{~cm}^3\) (STP)
Now, the carbonyl compound that can oxidise Tollens reagent is aldehyde and it is the oxidising product of \(1^{\circ}\) alcohol. So, among the given options 2, 2-dimethyl propan-1-ol (molecular mass \(=88\) ) is the required monohydric alcohol.
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